Newbie wants to watch Divx 700MB movie on Ipaq 2215

[Taxidermista]

[sponge]

[METROID]

[Neszis]

[That guy...]

Here goes something:

(fileseizeMB * 1024 * / lengthSeconds = bitrate

Lets say you had a 1h30m movie, and you wanted to fit it into 128MB.

(128 * 1024 * / 5400 = 194kbps

If you are encoding with AVI (DivX), you need to set aside some bits for the audio. Lets say you had 32Kbps audio. (Not needed for MPEG1)

194 - 32 = 162Kbps

This general method works for any application you can stick a bitrate into (Practically anything).

So if you were encoding MPEG1 the final bitrate would be 194Kbps, if you were encoding with AVI, the final video bitrate would be 194Kbps minus the audio.

Note for AVI encoding: Always use 2-pass, for the allocated bits make a better looking movie.

If all you wanted to know is how to encode a movie into 128MB then theres your answer, if you want to know how to actually encode a movie then you should find a tutorial on the program you intend to use.

[Guest]

damn smilies... the calcultions were supposed to be:

(fileseizeMB * 1024 * 8) / lengthSeconds = bitrate

And

(128 * 1024 * 8) / 5400 = 194kbps

[Neszis]

[MZGuy]

Bitrate is measured in bits per second and thus 194 kbps would be rougly 1.5 MB per minute of film, so Anonymous' math was completely correct.

[Neszis]

[sponge]

[Neszis]

[Presto]

[Neszis]

[sponge]

[Guest]

You are correct.

~Neszis~